Projectile on an Incline

11 Apr

Projectile on an Incline

Posted 11/04/2011 by rosapaulina in Physics. Tagged: classical mechanics, incline, inclined plane, mechanics, Physics, projectile. Leave a Comment

My Solution:

Based from the above figure point $\inline P(x,y)$ can also be denoted as $\inline (d\cos \phi , d\sin \phi)$ .

From kinematics equations for constant acceleration (at time t):

$x=vt\cos \theta$

$y=vt\sin \theta-4.9t^{2}$

It follows that

$d=\frac{vt\cos \theta}{\cos \phi}=\frac{vt\sin \theta-4.9t^{2}}{\sin \phi}$

$t=\frac{v\sin (\theta-\phi)}{4.9\cos \phi}$

Hence,

$d=\frac{v^{2}\cos \theta \sin (\theta-\phi)}{4.9\cos ^{2}\phi)}$

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